Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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counting gsame but a litle harder and less like 'oh i know what the enxt post will be kind of game'. in order to coutn you need to use matsh so to coutn 1 you dont say 1 you say 1*1 but try to refrain form easy maths and if ur ninja'd or have ur maths wrong the game is over and start from 1 again
can we count to 1K?
for mod feel free to lock if too spammy i readed the guidelines but i wasnt sure
thanks hg for making this much better and ty for my avatar aswell
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1
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1+1
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1+1+1
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1+1+1+1+1
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5+1+1
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x + -12 = -4
You Rock!
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1
in order to coutn you need to use matsh so to coutn 1 you dont say 1 you say 1*1
....
1+1
1+1+1
1+1+1+1
1+1+1+1+1
but try to refrain form easy maths
... alos add the final answer to your maths
thanks hg for making this much better and ty for my avatar aswell
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we have to start over now because someone broke the chain
1=1
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2=2
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⌠2
(│ 2x dx)=3
⌡1
I'm known as "haslo" in EE. Also, I refuse to play EEU.
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u need to put the number that it equals, we need to start over
1×1=1
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3+your age+5-your age-5=3
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The number is a number of “being”, it is the number that connects mind-body-spirit with the physical world of structure and organization.
You Rock!
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The number is a number of “being”, it is the number that connects mind-body-spirit with the physical world of structure and organization.
nope, there isn't equals at the end
2^0=1
I'm known as "haslo" in EE. Also, I refuse to play EEU.
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guys plese stay ontopic alrihgty
³SQRT 8=2
thanks hg for making this much better and ty for my avatar aswell
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⌠2
(│ 2x dx)=3
⌡1
I'm known as "haslo" in EE. Also, I refuse to play EEU.
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SQRT(2^4)=4
thanks hg for making this much better and ty for my avatar aswell
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10log(√(10))=5
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|D3| = 6
Where D3 is the dihedral group of a triangle.
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-2,6457513110645905905016157536393²=7
thanks hg for making this much better and ty for my avatar aswell
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