Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
You are not logged in.
Pages: 1
i have an equation:
i found roots for that equation:
1)
2)
3)
the problem is, i need to visualize these roots on the complex plane, but i have no idea how to do it when they are in trigonometric form, and afaik there is no way to convert it to algebraic form
Offline
there is some sort of smartt maths thingy called if im right wolfram aplha (google it) whihc ca maby help
thanks hg for making this much better and ty for my avatar aswell
Offline
Great, one more thing that 99% of the world will forget the second they graduate.
Great, one more thing that 99% of the world will forget the second they graduate.
Excuse me, but complex analysis is actually a field of mathematics that finds application in real life, for example, it is used in electromagnetism branch of physics.
Offline
Great, one more thing that 99% of the world will forget the second they graduate.
if i weren't interested in this i would've gone to this field to study complex numbers
Offline
This form is useful because cos θ + i sin θ represents a unit vector from the origin at angle θ anti-clockwise from the positive real axis, so that form effectively says that the lines from the origin to those points are of length root6(12) at angles -π/9, 5π/9, and 11π/9. When you plot these you'll also notice something else but I won't spoil the surprise just in case you haven't seen it yet
Offline
at angles -π/9, 5π/9, and 11π/9. When you plot these you'll also notice something else but I won't spoil the surprise just in case you haven't seen it yet
i instantly suspected something because i noticed that 5п/9 - (-п/9) = 11п/9 - 5п/9
but yeah i plotted it and that looks pretty cool
Offline
This form is useful because cos θ + i sin θ represents a unit vector from the origin at angle θ anti-clockwise from the positive real axis, so that form effectively says that the lines from the origin to those points are of length root6(12) at angles -π/9, 5π/9, and 11π/9. When you plot these you'll also notice something else but I won't spoil the surprise just in case you haven't seen it yet
Thanks, I also posted it on Reddit and got an answer
I knew about the symmetry, I knew about length or the vector and it's angles. But I only did that 1-2 times in class, so when I got home I got lost with cos() and sin()
Should've remembered that angle is the actual angle of the vector, no need for any cos sin calculations
Offline
Here is the result of anyone wonders
Offline
The world has been saved!
★ ☆ ★ ☆ ★
☆ ★ ★
Offline
Pages: 1
[ Started around 1732730561.0707 - Generated in 0.059 seconds, 13 queries executed - Memory usage: 1.51 MiB (Peak: 1.67 MiB) ]