Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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lets make a superlong math sproblem basically its simple person A makes a small maths problem like 1+1 person B calculates it and says its 3 2 then uses that 1+1 t omake a logner problem like (1+1)*2
you are allowed to:
- add bracklets to the previous problem if you want to keep that answer
- remove th ebrakclets added by the user before you
- reorder things to get an completely diffrent solution example: A: 3+1 B: 4 1+3*2 A: 7 2+3*1/5
- you always have to add atleast 1 extra number this could be done with just adding +1 on the end
- you have to use all th enumbers and symbols uses form the previous user but order does not matter as mentioned before
- grab a calculator if it get stoo difficult
- no variables such as 1+X it needs to be possible to calculate it
- you cna use + - * / ² ^ square-root Y-root ( ) , PI 1 2 3 4 5 6 7 8 9 0
- no ddouble posting its not fiar to calculate your own maths problem!
- forum rules
- negative numbers are allowed no such thing as infinty please because there is no infity
- you can use big numbers such as 1e45 or 1e78902 but please bear in midn that nto all calculators can use such big numbers if you find and number too big for your calculator and any other clauclator you tired just post it here so the previous poster can edit his maths problem give the poster a few hours and if he doesnt respond you are allowed to doubkle post and chnage that problem yourself
- please dont og offtopic it will ruin the game
- please alos let othe rpeople play this game too so not like A B A B A B C A D B A B ect but more like: A B C D B E F A G C H E D I J A B F G K C ect but if the topic is dying then you are always allowed to post to kepe the game alive
- don give the solution of your own math problem please
- if an problem is too long you can try to contact me and i will look ni the case if we shoudl start a new problem (if you have suggestions fo rthis rule please say it im not sure hwo to handle this rule because im not dsure when a porblem is considered too long)
EDIT: i forgot to start lol
7+8
thanks hg for making this much better and ty for my avatar aswell
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(7+8)/0
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(7+8)/0
Congratulations, you broke the equation.
(7+8)/0*0
(0+8)/7*0 there fixed
thanks hg for making this much better and ty for my avatar aswell
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(0+8)/7*0 there fixed
you are breaking the rules.
(Actually peace is asking for help with his homework)
(0+8)/7*0+4
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(Actually peace is asking for help with his homework)
(0+8)/7*0+4
The answer is 2
sqrt(-1)^(0+8)/7*0+4
Despite what people say, Different55 is the best mod.
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The answer is 2
sqrt(-1)^(0+8)/7*0+4
The answer is i^2
sqrt(-1 + e)^((0+8)/(7*0+4))
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272 wrote:The answer is 2
sqrt(-1)^(0+8)/7*0+4
The answer is i^2
sqrt(-1 + e)^((0+8)/(7*0+4))
False; that answer would actually be (i^8)/4, rather than 2, because of the order of operations.
The answer to your problem is e-1
sqrt(-1 + e)^0+8/(7*0+4)*pi (I suppose the excessive parenthesis are not needed, because the order of operations does the exact same thing for us already.)
Despite what people say, Different55 is the best mod.
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peace wrote:(0+8)/7*0 there fixed
you are breaking the rules.
- reorder things to get an completely diffrent solution example: A: 3+1 B: 4 1+3*2 A: 7 2+3*1/5
- you have to use all th enumbers and symbols uses form the previous user but order does not matter as mentioned before
alos enew rule: do ntot make a maths problem that is impossible such as 0/0 or so
thanks hg for making this much better and ty for my avatar aswell
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Anatoly wrote:peace wrote:(0+8)/7*0 there fixed
you are breaking the rules.
peace wrote:- reorder things to get an completely diffrent solution example: A: 3+1 B: 4 1+3*2 A: 7 2+3*1/5
peace wrote:- you have to use all th enumbers and symbols uses form the previous user but order does not matter as mentioned before
alos enew rule: do ntot make a maths problem that is impossible such as 0/0 or so
What counts as "impossible", because technically 0/0 is not "impossible", because it's answer is just quite simply, null.
Despite what people say, Different55 is the best mod.
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What counts as "impossible", because technically 0/0 is not "impossible", because it's answer is just quite simply, null.
such thigns as sqrt-3 its not possible (srt-1 is its answer is i)
thanks hg for making this much better and ty for my avatar aswell
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272 wrote:What counts as "impossible", because technically 0/0 is not "impossible", because it's answer is just quite simply, null.
such thigns as sqrt-3 its not possible (srt-1 is its answer is i)
That is possible though, sqrt(-3) is just a decimal multiplied by i. You just simply can't reduce it.
Despite what people say, Different55 is the best mod.
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(e-1)pi
(sqrt(-1+e)^0+8-4/(7*0+4)*pi^pi)+7
(sqrt(e-1)*pi^pi)+7
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Thanks HG for the signature and avatar!!!
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/lock the 2nd version by someone else lkkos bette rin my eyes i didn tplan this out too well so it became a mess
thanks hg for making this much better and ty for my avatar aswell
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