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Hi, I have an exam tomorrow but I do not really understand a question in my example exam. So if someone here could help me with it that would be cool.
Given is the differential equation Y" + aY' + bY = f(t)
The general solution is the sum of the homogeneous solution and the particular solution.
Given is Y" - 5Y' + 6Y = 6tˆ2 - 4t with Y(0)=5 and Y'(0)=4
Give the exact solution for Y(2)
I know the answer of the question, but there's no good explanation on how to get the answer. The given answer is:
y(t) =tˆ2 + t + 1/2 is the particular solution
Y(t)= Aeˆ2t + Beˆ3t + tˆ2 + t + 1/2 is the regular solution
Y(t) = 10.5eˆ2t - 6eˆ3t + tˆ2 + t + 1/2
Y(2) = 10.5eˆ4 - 6eˆ6 + 6.5
Getting the particular and regular solution is the part I don't understand, ofcourse the last two steps are not hard, and I understand those.
I know how to solve an equation that looks like Y"+aY+bY=0, but nowhere in my book can I find a question like this. So getting some help would be great
edit: i just looked at it again and I can find the regular solution after having the particular one, it's just solving Y" - 5Y' + 6Y = 0. Now I only struggle with finding the particular one.
edit2: Okay I got it, just say the solution must look like Y(t) = at^2 + bt + c and substitute. I was thinking waay to hard on this and this topic is useless now yay.
Pm me with anything math related please
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The notation is strange.
Y" is another notation for (d^2*Y)/(d*t^2) and Y' is another notation for dy/dt if that's what you mean.
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Oh so you’re talking about integrals. Can’t help here much. Just hope this exercise won’t be there.
Kind of, but now that I understand it it's pretty easy, so I hope the real exam will have a question like this
Pm me with anything math related please
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oh wow differential equations
what/where are you studying?
Final year of high school, I follow an extra math course with subjects that aren't in regular high school math. Nice part is that there's no final exam in this course, so I get to do 1 final exam less than other students in my country.
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