Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
You are not logged in.
Firecrackericebreak wrote:y = x * 25 + (x * 25) ^ 2
y = x * 25 + x^2 + 50x + 625um (x*25)(x*25)=x^2+625 its not (x+25)(x+25) so u dont times them all by each other
You're right
y = 25x + (25x)²
625x² + 25x - y = 0
Discriminant = b² - 4ac = 625-4*625*y = 3*625*y = 1875y
( -b +- D's Root ) : 2a = ( -25 +- √1875y) : 1250
x1 = (-25 + 25*√(3y)) : 1250 = 25(√(3y) - 1) : 1250 = 50(√(3y) - 1)
x2 = (-25 - 25*√(3y)) : 1250 = -25(√(3y) + 1) : 1250 = -50((√3y) + 1)
Firecrackericebreak wrote:y = x * 25 + (x * 25) ^ 2
y = x * 25 + x^2 + 50x + 625um (x*25)(x*25)=x^2+625 its not (x+25)(x+25) so u dont times them all by each other
is this right? y=25x+625x^2
625x^2+25x=0
(-25+(625-2500))/1250=-1.52
(-25-(625-2500))/1250=0.74
Where's y?
x1 = (-25 + 25*√(3y)) : 1250 = 25(√(3y) - 1) : 1250 = 50(√(3y) - 1)
x2 = (-25 - 25*√(3y)) : 1250 = -25(√(3y) + 1) : 1250 = -50((√3y) + 1)
umm that doesnt apparently work
use a functions grapher like this one to check your result
enter all of the three functions, if it's correct then you will see that the X1= and X2= functions will overlap with Y= function.
heres my result, i did it the same way as you (through discriminant)
X1 = (-1 - sqrt(1+4y))/50
X2 = (-1 + sqrt(1+4y))/50
you seemingly made a mistake somewhere and this line is where most likely it is:
Discriminant = b² - 4ac = 625-4*625*y = 3*625*y = 1875y
Offline
omg im so stupid i forgot about the y. would the y count as the c in the -4ac? in the end i got -1+-sqrt(1-4y)
----------------------
50
Est. December 2010
Offline
Offline
I don't need you anymore guys
you used me as a tool
Offline
Offline
Latif wrote:I don't need you anymore guys
you used me as a tool
Don't be sad I appreciated your help
might as well find a very useful tool not to come back to these forums anymore, would you
Instant hate
Offline
lol its not hard latif just substitute stuff in for -b+-sqrt(b^2-4ac) with y=ax^2+bx+c
----------------------
2a
Est. December 2010
Offline
Offline
i suck at maths i only know 1x and 10&11 X
Offline
Offline
[ Started around 1732965979.8989 - Generated in 0.087 seconds, 12 queries executed - Memory usage: 1.58 MiB (Peak: 1.77 MiB) ]