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I've been very confused with division by 0. So i decided to ask you what 1/0 is
What would be your answer to this math operation?
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You cant divide by 0 because :
lets do some work
5 x 4 = 20 right?
20 : 4 = 5, 20 : 5 = 4 .
But
5 x 0 = 0
You cant get 5 when you divid 0 by 0.
0 : 0 =/= 5.
or it is = ?
It means if we divid 0 by 0 we can get 5 or anything like 1, 2 , 3, 4 etc
Also 0 is not negative or positive number, it is nothing.
thats why we also can get -1, -2, -3, -4 etc
so
X : 0 = Infinity. Infinity infinity. with all numbers what even possible.
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You cant divide by 0 because :
lets do some work5 x 4 = 20 right?
20 : 4 = 5, 20 : 5 = 4 .But
5 x 0 = 0
You cant get 5 when you divid 0 by 0.0 : 0 =/= 5.
or it is = ?It means if we divid 0 by 0 we can get 5 or anything like 1, 2 , 3, 4 etc
Also 0 is not negative or positive number, it is nothing.
thats why we also can get -1, -2, -3, -4 etcso
X : 0 = Infinity. Infinity infinity. with all numbers what even possible.
The answer to that is that 0 * infinity = 1 after 1/0 = infinity and 1/infinity = 0
Doing that operation is exactly like doing 0/0. You will get different results according to the formats and laws you use.
You can divide by 0 as x/0 = infinity and x/infinity = 0. But 0*infinity is an indeterminate form here.
0/0 is an indeterminate forum because it can give 1, 0 or an infinity. Same happens with 0*infinity. It can give 1 after x*1 / x = 1 when x = 0
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divided by 0 error
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gosh, Math sucks
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Dividing by 0 doesn't make any sense.
But 0 divided by a number is possible and gives 0 as result.
Multiplying by 0 gives also gives 0.
I made a quick equation for you:
a = b = 1
<=> (a + b)(a - b) = 0 <=> (a + b) = 0 / (a - b) => (a + b) = 0
But a = b = 1 that means (1 + 1) = 0 => 2 = 0 which is a nonsense.
Edit: Math is one of the oldest science. If theres a rule then it is for a good reason.
For the good of men kind, please stop reinventing it.
Everybody edits, but some edit more than others
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Dividing number by 0 give you infinity number
and
Any number + / - / * / : on any number gives you 2 results:
a + b = c and 0
a - b = c and 0
a * b = c and 0
a : b = c and 0
or not?
Math suck anyways
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Dividing number by 0 give you infinity number
and
Any number + / - / * / : on any number gives you 2 results:
a + b = c and 0
a - b = c and 0
a * b = c and 0
a : b = c and 0or not?
Math suck anyways
The divisor, in your case b, must be different from 0.
Basically: (∀) b ≠ 0, a / b = c
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Imagine you have 0 cookies and want to spread them with 0 friends.(you make up de one)
Makes no sense right?
Cookie monster is sad cuz there is no cookies
You are sad cuz u have no friends
How long will it take me to get banned again?
Place your bets right here.
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Imagine you have 0 cookies and want to spread them with 0 friends.(you make up de one)
Makes no sense right?
Cookie monster is sad cuz there is no cookies
You are sad cuz u have no friends
\
I can give 5 cookies to 0 friends
every friend will get 0 cookies
#math_sucks
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Imagine you have 0 cookies and want to spread them with 0 friends.(you make up de one)
Makes no sense right?
Cookie monster is sad cuz there is no cookies
You are sad cuz u have no friends
Siri from iPhone/iPad/iPod told you that, right?
Even it says that 0/0 is indeterminate.
Converting this topic into official math topic...
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#MathIsLifeMathIsLove
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infinity is a concept, not a number
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Lets go back to basics... You have 5 things and you put in into 0 groups. 0 groups means 0 things. EZPZ
F
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Lets go back to basics... You have 5 things and you put in into 0 groups. 0 groups means 0 things. EZPZ
I said the same thing
Luka504 wrote:Imagine you have 0 cookies and want to spread them with 0 friends.(you make up de one)
Makes no sense right?
Cookie monster is sad cuz there is no cookies
You are sad cuz u have no friendsI can give 5 cookies to 0 friends
every friend will get 0 cookies
#math_sucks
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In most cases where "division" is defined as an operation it is simply multiplying by the inverse of the divisor. In order for it to be well defined, the divisor does not have an inverse. In any ring (except the ring of one element, which may not even be defined depending on the definition of ring you choose), the "additive" identity does not have a "multiplicative" inverse. Within the rings of integers, rational numbers, and real numbers given with operations + and × (standard addition and multiplication), the additive identity is the number 0. As a result, 0 does not have a multiplicative inverse, meaning that division by 0 makes no sense to be defined in the normal sense in which one would define division on a ring/field (fields being the mathematical object where division usually appears).
There are some other senses in which division could be defined. For example, instead of using anything to do with rings we could use the definition of divisibility over the integers. By this definition, a divides b if b=qa for some integer q. In order for 0 to divide 1, it would be necessary to find an integer q such that 1=q×0. However, for all integers, q×0=0, so this is impossible. Thus, 0 cannot divide 1.
Additionally, it could potentially be possible to define 1/0 specially by taking a limit using calculus. This approach is fairly similar to what is given by HG; the positive sided limit approaches positive infinity, and the negative sided limit approaches negative infinity. Since these aren't equal, there is no limit (finite or infinite) for 1/x as x approaches 0. However, even if the limit were to be positive infinity on both sides, it would not necessarily make sense to define 1/0 as positive infinity.
While it is possible to construct number systems in which infinity is a number, these systems always end up having significantly different properties from the more familiar number systems (integers, rationals, and reals). The most basic example of a number system with infinity in it would be the extended real numbers; in this case, the problem of having infinity as a number is solved by making even more potential operations undefined. It isn't a field, or even a group, and its main use is as a notational convenience in analysis.
Another system would be the real projective line, which only has a single point of infinity (rather than positive and negative ones). In fact, under this system, 1/0 actually is defined as infinity (essentially; this is a slight simplification). However, using this system leads to other complications that are not necessary or helpful for normal mathematics. Other number systems with infinity include the hyperreal numbers and the surreal numbers, used in non-standard analysis and and set theory respectively. Both of these are fields like the real numbers, and even though they have infinity don't define 1/0. They (particularly the surreals) are quite complicated to use, and for a number of reasons the real numbers are preferred for, well, most things.
Most of this information was probably not very relevant to the topic but whatever. TL;DR: in most contexts it doesn't make sense to define 1/0. In the ones where we do, it generally has to be some sort of infinity. However, treating infinity as a number adds its own complications that we don't usually want to deal with. In fact, even when we treat infinity as a number, it's usually better not to define 1/0. It just rarely makes any sense to define it.
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Well, indeed, concepts are a different subject.
The concept of your problem may give a ±∞.
You may be also familiar with the imaginary number concept i² = -1 By normal rules i can't exist, but however it is used.
Edit: TL;DR; its just a convenient for mathematical fiction.
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Why not just use L'Hôspitál?
If you're just trying to evaluate 1/0 you're going to be in a pickle (and I think we've beat that horse into nonexistence) but if instead you have a limit which approaches x/0 or inf/0 or something like that, then you can use L'Hôspitál to reveal the actual answer.
An example:
lim x->0 [sin(x)/x] => 0/0
lim x->0 [sin(x)/x] == lim x->0 [cosx/1] == 1
This also demonstrates why x/0 needs to be undefined. Notice in the first statement I said => 0/0 instead of == 0/0. If I said it equals 0 then I could then say
lim x->0 [sin(x)/x] == 0/0
lim x->0 [2x/x^2] == 0/0
therefore
sin(x)/x == 2x/x^2
1 == 2
which is definitely false.
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Since this is now the "official" math topic (and I am a math major #jealous?) I'd like to transition into something far more fascinating than illogical division. This idea of indeterminate forms having actual values is found elsewhere. Riemann unintentionally discovered this with his Zeta function.
ζ(s) = Σ(n=0, inf) [1/n^s]
This is essentially the sum of all the inverses raised to the power n.
This is super cool because you can use analytic continuation to find values for negative numbers.
What happens when you plug in negative numbers?
ζ(-1) = 1 + 2 + 3 + 4 + ...
You can see how this series goes to infinity. However, if you "remove" the infinite part of this function via analytic continuation, you get an incredibly fascinating answer: -1/12.
Negative one twelfth.
This answer might seem "stupid" but it is quite legitimate if you think of the series not in terms of simple addition but as an infinite sum, outside the bounds of what we can comprehend.
Yeah, well, you know that's just like, uh, your opinion, man.
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Five times nine is at least forty
5a = 45 if a=9
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Onjit wrote:Five times nine is at least forty
5a = 45 if a=9
nine may be + and -
it means
5a = b
If a = 9 , b = 45
If a = -9 , b = -45
5a = +-45
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whats square root of -4?
F
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whats square root of -4?
2i
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