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kurtv13

Member

From: Everywhere

Joined: 2015-04-24

Posts: 59

[SOLVED] Getting background color from "init"

init returns the background color of a world as a uint. How do I convert this value back to hex code or rgb?

example, #000080 becomes 4278190208 edit: how do I convert 4278190208 back to #000080

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ewoke

Member

Joined: 2015-02-20

Posts: 412

Re: [SOLVED] Getting background color from "init"

capasha has it somewhere in his code, check his website capasha.com

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if you can read this....good for you

kurtv13

Member

From: Everywhere

Joined: 2015-04-24

Posts: 59

Re: [SOLVED] Getting background color from "init"

I'm not quite sure what I'm looking for here. Is it some source code for a converter?

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ewoke

Member

Joined: 2015-02-20

Posts: 412

Re: [SOLVED] Getting background color from "init"

its in his minimap project iirc but im not sure

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if you can read this....good for you

capasha

Member

Joined: 2015-02-21

Posts: 4,066

Re: [SOLVED] Getting background color from "init"

        public static Color UIntToColor(uint color)
        {
            byte a = (byte)(color >> 24);
            byte r = (byte)(color >> 16);
            byte g = (byte)(color >> 8);
            byte b = (byte)(color >> 0);
            return Color.FromArgb(a, r, g, b);
        }
Color color UintToColor(4291715791);
var hex = "#" + color.R.ToString("X2") + color.G.ToString("X2") + color.B.ToString("X2");

This code is the code to make hex colors.

TiKen

Member

Joined: 2015-02-24

Posts: 298

Re: [SOLVED] Getting background color from "init"

This integer is the decimal form of an ARGB color (A being alpha, coding the transparency is set at 255).

So if you transpose 4278190208 to hexadecimal, you'll find #FF000080

kurtv13

Member

From: Everywhere

Joined: 2015-04-24

Posts: 59

Re: [SOLVED] Getting background color from "init"

Thank you very much

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rubixguy

Member

Joined: 2015-03-19

Posts: 27

Re: [SOLVED] Getting background color from "init"

        public static Color UIntToColor(uint color)
        {
            byte a = (byte)(color >> 24);
            byte r = (byte)(color >> 16);
            byte g = (byte)(color >> 8);
            byte b = (byte)(color >> 0);
            return Color.FromArgb(a, r, g, b);
        }
Color color UintToColor(4291715791);
var hex = "#" + color.R.ToString("X2") + color.G.ToString("X2") + color.B.ToString("X2");

This code is the code to make hex colors.

Or you could just use this to do the conversion from uint to Color:

Color.FromArgb(unchecked((int)m.GetUInt(19)));

But depending on your build settings, unchecked is probably used by default, in which case, you can use:

Color.FromArgb((int)m.GetUInt(19));

EDIT:

But to get to the hexadecimal value, I would use this:

"#" + m.GetUInt(19).ToString("X8");

EDIT 2: Forgot that you probably don't want the alpha value in there

"#" + (m.GetUInt(19) & 0xFFFFFF).ToString("X6");

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