Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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First of all...
I sacrifice myself and all my powers to create a hill that is impossible to conquer, destroy, etc. It's aboslutely impossible to get it except the poster who answers correctly to the next questions:
1. Jess threw a x number of arrows to a target divided in 3 parts. The red part is worth 10 points, the orange one 8 and the yellow one 5. Jess missed 1/4 of the arrows thrown. She managed to hit the same number of arrows in the red part and in the orange part. All arrows scored 200 points in total. How many arrows did Jess throw?
2. Joe wants to bake a cake using only milk, sugar and flour, following this recipe: the weight of the flour must be the double of the weight of milk and the weight of sugar must be one third of the weight of flour. If he wants to bake a cake with a total weight of 1100g, what is the amount of milk, in grams, that Joe needs?
If a person manages to get these questions right, he will win this game. PERMANTENTLY.
I garantee that these questions are 100% possible.
P788 said nothing about not being able to invert the hill.
Second of all, he said nothing about not being able to make our own hill.
You disappear in a puff of logic.
My hill.
Last edited by some man (Nov 17 2012 7:27:06 am)
10 years and still awkward. Keep it up, baby!
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I bury you (huffpuff) in the hill.
Now its my hill.
huffpuff, who was buried in the hill back at my first post in this game (Waaaay back on page 62!) wakes from the dead, obviously disturbed by the havoc up here, and pulls you into his grave...
My hill
No wait!
I lose my footing and tumble into the abyss as well.
Someday I might escape...
Next posters hill.
Last edited by Geist (Nov 17 2012 3:58:56 pm)
My hill
some man, you have been arrested because Geist has told us your identity.
Deetz, you drowned in your sig.
Our hill (me Geist P788)
I bash a hole through the wall in prison, and go back on my hill.
My hill.
10 years and still awkward. Keep it up, baby!
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SOME. MAN. YOU. NEED. TO. ANSWER. THE. QUESTION. PERIOD.
Our hill (me Geist P788)
You disappear due to the question's hardness.
Our hill (me Geist P788)
I summon N1KF, and together we ultimately go back in time and delete the existence of the questions you made.
Our hill.
10 years and still awkward. Keep it up, baby!
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WAIT! Last minute entry! For Number 3, the answer is 21 ways. I already got the other 2.
PEOPLE!!! SROP BEIN NUBS AND ANSWER THE QUESTIONS! ESPECIALLY YOU, SOME MAN!
Our hill (me Geist P788)
Gawddarnit for cryin' out loud could you just change the question?
(Even though it's still um...[I think it was Team Fortress]whoever's hill.)
Signature last updated 7 Feb 2020 2:08 AM PST (-8 UTC)
Basically inactive but I'll come in sometimes and yeah who the funk am I kidding I don't visit here anymore. check out my totally legit avi tho I made it when I was like 14
Best of luck to you all in your lives. Thanks for all the good times.
~greg³
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WAIT! Last minute entry! For Number 3, the answer is 21 ways. I already got the other 2.
I'm sorry... The answer is wrong.
I'm going to replace the question #3. It's in the bottom of this post.
So I can reveal the solution. It's 172.
And why? Read this solution:
3. In a train carriage there were 6 persons: Abe, Bill, Cindy, Daniel, Eddy and Finn. During the trip they noticed that each one of them had the same number of friends in that carriage. How many ways can this happen?
To visualize the different possibilities in the friendships between the 6 persons in the carriage, we represent each person by a point, and we trace a line segment between 2 points to indicate that the correspondent people are friends.
There are several cases to consider.
- Case 1: Everybody has 0 friends in the carriage. In our representation, that means that there's no connection between the 6 points. So there's only 1 way of happening that.
- Case 2: Everybody has 1 friend in the carriage, that corresponds to unite the 6 persons in pairs, like this:
Abe can have 1 of 5 possible friends. From the remaining 4 persons, the first from alphabetical order can have 1 of 3 possible friends, and the remaining pair is already determined. In this case, there are 5 x 3 = 15 possibilities.
- Case 3: Everybody has 2 friends in the carriage. Abe can get any pair from the 10 pairs of friends (BC,
BD, BE, BF, CD, CE, CF, DE, DF and EF, where each letter represents the initial of each person). If the Abe's friends are friends between them, then the friendships are determined and the configuration is this:If they aren't friends between them, then the only possible configuration is the following:
In this case, the first friend of Abe by alphabetical order can choose between 3 friends and the other can choose between 2 friends. So, in this configuration, there are 10 x 3 x 2 = 60 possibilities. So, in this case, there are 10 + 60 = 70 possibilities.
- Case 4: Everybody has 3 friends in the carriage. This case is similar to the case where everybody has 2 friends, because having 3 friends corresponds to having 2 "non-friends". Which means that there are also 70 possibilities in this case.
- Case 5: Everybody has 4 friends in the carriage. This case corresponds to everybody having 1 "non-friend", which gives 15 more possibilities.
- Case 6: Everybody has 5 friends in the carriage. There's only 1 way of happening that.
So, the total is 1+15+70+70+15+1= 172 ways of happening that everybody has the same number of friends in that carriage.
Did everybody unterstand? Then solve this question:
Matt calculated the product of the non null digits of every integer from 1 to 2012. After that, he calculated the sum of all those 2012 products. What was the number obtained by Matt?
Team Fortess's Hill (P788, Geist and Levelbuilder0728).
PEOPLE!!! SROP BEIN NUBS AND ANSWER THE QUESTIONS! ESPECIALLY YOU, SOME MAN!
Our hill (me Geist P788)
We duneed to.
Team Derp's hill.
10 years and still awkward. Keep it up, baby!
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Levelbuilder0728 wrote:PEOPLE!!! SROP BEIN NUBS AND ANSWER THE QUESTIONS! ESPECIALLY YOU, SOME MAN!
Our hill (me Geist P788)
We duneed to.
Team Derp's hill.
I trap Team Derp in a box that is indestructable, impossible to teleport to outside it, impossible to die and respawn outside it, or anything that allows you to escape it. It's impossible to escape, period. If you escape it, you cease to exist.
Team Fortress's hill (P788, Geist and Levelbuilder0728).
A poor team named Team Derp is now trapped in a box for eternity. We changed the name of our team to Team Derps.
Team Derps casts a fishing rod on the chair you are sitting on, reels it back, and it falls in a pit of lava.
Team Derps's hill.
Last edited by some man (Nov 19 2012 5:33:13 pm)
10 years and still awkward. Keep it up, baby!
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I pull myself out of the ground at last, grab a 1965 Wham-O Super Ball and fling it at you, the heavy rubber ball causes you to need medical attention. The entire Derp team go to the hospital as well to purchase get well soon balloons and crummy hospital snacks. Since the hill is empty, I claim it.
My team moves on it...
So I quickly leave to buy P788 and his squad some solar cookers and get in a traffic jam along the way to the department store.
P788's team hill.
You just changed your name, some man. It still traps you.
Our hill (me Giest P788)
One crummy hospital snack makes me have superpowers, I share it with N1KF and the rest of Team Derps, and together we ultimately destroy the hill and make a hill that towers ten lightyears into space.
Team Derps's hill.
10 years and still awkward. Keep it up, baby!
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I return to the hill, and using my newly bought solar cookers, use the reflector and shine it in your eyes, you fall backwards into huffpuff's grave from page 62.
I charge up the hill to claim it, but then the next poster parachutes down and kicks my kneecap and I slide down the hill into a ditch, clutching my wounded knee.
Next posters hill, temporarily.
That was a clone of Team Derps.
Team Derps's hill.
10 years and still awkward. Keep it up, baby!
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That was a clone of Team Derps.
Team Derps's hill.
You can't escape the box you are in.
The only way to get the hill is by answering this question:
Matt calculated the product of the non null digits of every integer from 1 to 2012. After that, he calculated the sum of all those 2012 products. What was the number obtained by Matt?
Team Fortress's hill (P788, Geist and Levelbuilder0728).
Screw the question, I move on.
My hill.
lunchbox
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The hill tips over and falls on the box, effectively destroying it.
Team Derp's hill.
10 years and still awkward. Keep it up, baby!
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