Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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9.
This is a false statement.
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!9.
11.
As offtopic as this is, I need to provide the correct answer:
10
I am well aware that it has been too long since the time permissed to answer.
edit: nvm i have no idea what it is
Last edited by GKAbyss (Dec 17 2014 12:27:53 pm)
!=Order possibilities.
!0=0!=0
9+0=0
Are you sure, GKA?
This is a false statement.
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!=Order possibilities.
!0=0!=0
9+0=0Are you sure, GKA?
Normally you wouldn't put it on the left if that's what you meant.
Also 0!=1.
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9+0=0
Please tell me that you're joking.
Last edited by ILoveBacon (Dec 17 2014 12:54:27 pm)
Creature wrote:9+0=0
Please tell me that you're joking.
Nah, i mistaked, i meant 9.
Also, 0!=0, its impossible.
Last edited by Creature (Dec 17 2014 1:04:12 pm)
This is a false statement.
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No, 0!=1. This is information that is very easy to look up.
All of the above definitions incorporate the instance
0! = 1
in the first case by the convention that the product of no numbers at all is 1. This is convenient because:
There is exactly one permutation of zero objects (with nothing to permute, "everything" is left in place).
http://en.wikipedia.org/wiki/Factorial
What About "0!"
Zero Factorial is interesting ... it is generally agreed that 0! = 1.
It may seem funny that in this case multiplying no numbers together results in 1, but it helps simplify a lot of equations.
http://www.mathsisfun.com/numbers/factorial.html
The special case 0! is defined to have value 1, consistent with the combinatorial interpretation of there being exactly one way to arrange zero objects (i.e., there is a single permutation of zero elements, namely the empty set ).
http://mathworld.wolfram.com/Factorial.html
Last edited by Ratburntro44 (Dec 17 2014 2:06:48 pm)
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What is this doing in general discussion, just asking.
Nothingness will never be 1, wikipedia sometimes give the wrong info due a stupid myth.
This is a false statement.
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Nothingness will never be 1, wikipedia sometimes give the wrong info due a stupid myth.
He gave more than one source. It's hard to question the reliability of what he said.
thx for sig bobithan
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Nothingness will never be 1, wikipedia sometimes give the wrong info due a stupid myth.
Stop being obtuse. I gave two sources besides Wikipedia, one of them being Wolfram MathWorld (a pretty reliable source). If you want an additional source, the same definition is given on section 2.3 page 151 of Discrete Mathematics and Its Applications by Kenneth H. Rosen. If you enter it into WolframAlpha it gives you 1 for 0!. There's even a website called zero factorial. They have their own sources. Additionally, the analytic extension of the factorial function, the gamma function, gives a matching result.
This is not a source of any serious disagreement at all. It is widely and essentially completely agreed that the factorial of 0 is 1. You are, very simply, wrong.
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If 1!=1.0=1, then why 0!=0.0=1?
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I'm not sure what you're using a decimal point to indicate there (maybe multiplication?), but there are multiple explanations for why 0!=1 from different perspectives.
1) You can have 0!=1 by definition, allowing you to define all other factorials as n!=n(n-1)! for n in Z, n>0.
2) The set with 0 elements is the empty set. There is one way to order the empty set (even though the ordering is simply nothing).
3) If you take that for any n in Z, n>=0, n!=n(n-1)(n-2)*…*1, then doing this for n=0 would give you a product of 0 factors, which is taken as 1.
Last edited by Ratburntro44 (Dec 17 2014 7:35:54 pm)
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ok so it seems like you guys dont know so
the person who made this topic said 9 + !0 because they were holding shift while making the title, so it made 1 a !
damn you guys suck
Last edited by Bimps (Dec 17 2014 2:49:28 pm)
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I'm not sure what you're using a decimal point to indicate there (maybe multiplication?), but there are multiple explanations for why 0!=1 from different perspectives.
1) You can have 0!=1 by definition, allowing you to define all other factorials as n!=(n-1)! for n in Z, n>0.
2) The set with 0 elements is the empty set. There is one way to order the empty set (even though the ordering is simply nothing).
3) If you take that for any n in Z, n>=0, n!=n(n-1)(n-2)*…*1, then doing this for n=0 would give you a product of 0 factors, which is taken as 1.
So here's why, its 0 but they take it as 1. Nonsense.
Bimps, if he mistaked, he would warn us.
This is a false statement.
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It's !9. Am I right Killeratz
Bimps, if he mistaked, he would warn us.
maybe he didnt look at the title or isnt on this forum 24/7 like you
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Do I really need to tell you the reason why the product of zero numbers is 1?
Take a product of n numbers. Now take away each of these numbers by dividing it by them. You are left with a product of 0 numbers after having divided the number by all of its factors. After dividing the number by its factors, the number you are left with is 1. 1 is the product of 0 factors.
Other ways of saying it: 1 is the multiplicative identity. 1 is the product of an empty set of numbers for the same reason 0 is the sum; 0 is the additive identity. This is also the same reason that any number exponentiated to 0 gives 1.
0! is not 0 at all, and this is for very good reasons that are not very complicated.
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9.
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Incomplete Input
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