Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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I sees a deraining coming on.
Fun level, raged
Well, the maths was the easy part. With a keyboard that has almost run out of battery, the lag was too much to continue on my quest to the great circle.
Thank you eleizibeth ^
I stack my signatures rather than delete them so I don't lose them
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0/0 can be 0 or be infinite, but I don't know how that can be 1 '-'
0/0 can be 0 or be infinite, but I don't know how that can be 1 '-'
You shouldn't divide when using powers...
Anyways, if you take a branch of math at University/College (depending on where you come from, I am pretty sure you will get a better definition why it equals 1.
And that stuff that you posted before, it is a mathematical paradox.
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x = y
x^2 = xy
x^2-y^2 = xy-y^2
(x+y)(x-y) = y(x-y)
x+y = y
2y = y
2 = 1
1 = 0
It's stupid :
You know (I think) that it's impossible to do x/0. Look at your calculator or ask your teacher, or just be logic, you can't divise a cake in 0 part.
And here you divide and multiply by x or y (same number because x=y)
And you know (I think) that x or y can be all the number, 0 including.
So it's impossible, or the result is 0=0
Same exemple here :
2y = y (real résult of the équation is 0, of course)
(2y)/y = y/y (here you divide by y, so maybe by 0, imposs)
(2y)/y = 1
2x(y/y) = 1
2 x 1 = 1
2 = 1
I won, you saw, not that hard acutally. It was fun for me.
It'd be nice if you made more and harder stuff
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Awesome level.
I had to go at 11 coins though. :c
bennyboy1251 wrote:x = y
x^2 = xy
x^2-y^2 = xy-y^2
(x+y)(x-y) = y(x-y)
x+y = y
2y = y
2 = 1
1 = 0It's stupid :
You know (I think) that it's impossible to do x/0. Look at your calculator or ask your teacher, or just be logic, you can't divise a cake in 0 part.
And here you divide and multiply by x or y (same number because x=y)
And you know (I think) that x or y can be all the number, 0 including.
So it's impossible, or the result is 0=0Same exemple here :
2y = y (real résult of the équation is 0, of course)
(2y)/y = y/y (here you divide by y, so maybe by 0, imposs)
(2y)/y = 1
2x(y/y) = 1
2 x 1 = 1
2 = 1
Its just a joke Lictor666.
You shouldn't divide when using powers...
but
x^-1=x/x/x
x^-2=x/x/x/x
x^-3=x/x/x/x/x
so x^0=x/x
Last edited by maegor (Jan 2 2013 3:49:24 pm)
Doctor_downes wrote:You shouldn't divide when using powers...
but
x^-1=x/x/x
x^-2=x/x/x/x
x^-3=x/x/x/x/xso x^0=x/x
But 0 isn't negative.
It is seen as a positive number in the mathematics community
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neither positive, nor negative
but whatever
x^5 = x*x*x*x*x
x^4 = x*x*x*x
x^3 = x*x*x
x^2 = x*x
x^1 = x
x^0 = x/x
x^-1= x/x/x
x^-2= x/x/x/x
x^-3= x/x/x/x/x
It's impossible to be more logical
neither positive, nor negative
but whateverx^5 = x*x*x*x*x
x^4 = x*x*x*x
x^3 = x*x*x
x^2 = x*x
x^1 = x
x^0 = x/x
x^-1= x/x/x
x^-2= x/x/x/x
x^-3= x/x/x/x/xIt's impossible to be more logical
Even if that is the case, why are you including the power 0 as a negative number?
x^2=x^2
x^1=x
x^0=1
x^-1=1/x
x^-2=1/x^2
Last edited by Doctor_downes (Jan 2 2013 5:10:28 pm)
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1/x = x/x/x
1/x^2 = 1/x*x = x/x/x/x
division don't means that 0 is negative '-'
Even if you are doing it that method, x/x for 0 is 1.
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so 0/0=1?
@edit
forget the discussion, i did the sanity test , 0/0 can be any number. +rep for opening my mind
@edit2
your rep is disabled
Last edited by maegor (Jan 2 2013 5:43:44 pm)
so 0/0=1?
You are using x, meaning any number, so in that instance yes.
x/x can be simplified to 1, therefore you needn't substitute x back.
So, theoretically you disproved yourself, by using the proof.
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The thing I hate most in the world is trigonometric identities.
I'm trying the level
Win. It was a fun challenge, keep up the good work.
None got 3 blue coins.
RedHat used Golden Shovel, it's super effective.
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Thanks to eedd, I showed I was 2pr04him.
Nice level.
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