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0^1/0 = 1, because 0^0 = 1.
0^2/0^1 = 0^1, becuse of a rule of exponents.
Simply everything, you get:
0/0 = 1
0/0 = 0
So, 1=0. 1=0 is obviously nonsense, right? Those "professional" math people need to do something to this.
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#Joe Griffin
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0^1/0 = 1
no?
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Those "professional" math people need to do something to this.
yes
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what
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0^1
is 0
/0
is infinity
0^2
is 0
0^1
is 0 too, so
0^2/0^1
is infinity
0/0 = 1
0/0 = 0
and where did you take this, I don't know
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2 + 2 is 4 - 1 is 3 quick maths
Wrong, 0/0 = %
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Maths geeks already did fix this
The problem arises from both 0^0 and 0/0 having multiple solutions depending on how you look at them
x^0 = 1 and 0^x = 0, but with x=0 these both give the same equation but different answers
The same with 0/x = 0 and x/x = 1
This is solved by saying that things like 0^0 and 0/0 are 'undefined', and giving equations a range of values which they are valid for, for example x^0=1 x≠0, and (x^2)^(1/2) = x x≥0
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0^1/0 = 1, because 0^0 = 1.
0^0 is indeterminate form
0^1/0 is 0/0 which is also indeterminate form
this thread is bad please delete
Wrong, 0/0 = %
What? How come Luka wooted this post instead of disagreeing with it and starting another long debate?
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Maths geeks already did fix this
![]()
The problem arises from both 0^0 and 0/0 having multiple solutions depending on how you look at them
x^0 = 1 and 0^x = 0, but with x=0 these both give the same equation but different answers
The same with 0/x = 0 and x/x = 1This is solved by saying that things like 0^0 and 0/0 are 'undefined', and giving equations a range of values which they are valid for, for example x^0=1 x≠0, and (x^2)^(1/2) = x x≥0
__
\/-1 used to be undefined. But now it is i.
Undefined values are cheating.
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#Joe Griffin
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__
\/-1 used to be undefined. But now it is i.
Undefined values are cheating.
The difference is that root -1 can be used algebraically without breaking any of the existing rules, 0/0 and 0^0 don't do this so they have to be undefined, otherwise you end up with things like your original statement of 0 = 1
The great thing about Maths is that you can take take a statement and prove that it is true given some original statements, the reason this works is that the rules are constructed in a way that means that there will never be any contradictions, so there is no other option than to say that 0/0 and 0^0 are undefined, otherwise the whole of Maths won't work It isn't us saying 'we don't know the answer', its just the way things are, there *cannot* be a single answer.
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never divide by 0
if you divide x=1/(5+3-8)
x = 1/5 + 1/3 - 1/8 = 3/15 + 5/15 - 1/8 = 24/120 + 40/120 - 15/120=64/120 - 15/120 = 49/120 = x
you'll have different results
when you divide same thing by x=1/(2+3-5)
x = 1/2 + 1/3 - 1/5 = 5/6 - 1/5 = 25/30 - 6/30 = 19/30 = x
19/30 = 76/120 =/= 49/120
you'll get another result, even if 2+3-5 = 5+3-8
because 2+3-5=0, and 5+3-8=0
that's why you can't divide by 0
0^1/0 = 1, because 0^0 = 1.
0^2/0^1 = 0^1, becuse of a rule of exponents.
so in both examples you divided by 0
The great thing about Maths is that you can take take a statement and prove that it is true given some original statements, the reason this works is that the rules are constructed in a way that means that there will never be any contradictions, so there is no other option than to say that 0/0 and 0^0 are undefined, otherwise the whole of Maths won't work It isn't us saying 'we don't know the answer', its just the way things are, there *cannot* be a single answer.
my opinion about 0^0 is 1
because 0^3 = (infinity amount of 1s)... 1*1*1*0*0*0*1*1*1...(infinity amount of 1s) = 1
so 0^0 = (infinity amount of 1s)...1*1*1*1*1...(infinity amount of 1s)
because 1 times everything = it self
that's how x^0 work according to my opinion
and that makes it not undefined
noone said that you can't do powers of 0, you only can't divide
even google say that 0^0 = 1, and 0/0 is undefined, so you shoudn't say that 0^0 is undefined
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never divide by 0
if you divide x=1/(5+3-8)
x = 1/5 + 1/3 - 1/8 = 3/15 + 5/15 - 1/8 = 24/120 + 40/120 - 15/120=64/120 - 15/120 = 49/120 = x
you'll have different results
when you divide same thing by x=1/(2+3-5)
x = 1/2 + 1/3 - 1/5 = 5/6 - 1/5 = 25/30 - 6/30 = 19/30 = x
19/30 = 76/120 =/= 49/120
you'll get another result, even if 2+3-5 = 5+3-8
because 2+3-5=0, and 5+3-8=0
that's why you can't divide by 00^1/0 = 1, because 0^0 = 1.
0^2/0^1 = 0^1, becuse of a rule of exponents.so in both examples you divided by 0
LukeM wrote:The great thing about Maths is that you can take take a statement and prove that it is true given some original statements, the reason this works is that the rules are constructed in a way that means that there will never be any contradictions, so there is no other option than to say that 0/0 and 0^0 are undefined, otherwise the whole of Maths won't work It isn't us saying 'we don't know the answer', its just the way things are, there *cannot* be a single answer.
my opinion about 0^0 is 1
because 0^3 = (infinity amount of 1s)... 1*1*1*0*0*0*1*1*1...(infinity amount of 1s) = 1
so 0^0 = (infinity amount of 1s)...1*1*1*1*1...(infinity amount of 1s)
because 1 times everything = it self
that's how x^0 work according to my opinion
and that makes it not undefined
noone said that you can't do powers of 0, you only can't divide
even google say that 0^0 = 1, and 0/0 is undefined, so you shoudn't say that 0^0 is undefined
Here is how I understand it:
x^0 is a simplified way of writing x^2/x^2 (or any other exponent over the same). You subtract the exponents and remove the denominator and end up with x^0. Tho an even simpler (and more obvious) way is simplifying this to just 1. BUT what if x equals 0? 0^0 alone seems like it checks out, but that'd mean you could also write it as 0^2/0^2, which is also equal to 0/0 which is division of zero. So I'd think 0^0 would be undefined. Anything to the 0th power equals itself over itself, which results in 1 in seemingly every case except for 0.
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Who cares what you think, Azurepudding? It's been proven that 0^0 is indeterminate, your opinion doesn't matter.
There's nothing special about assuming something false and arriving at a contradiction. It's called the principle of explosion, look it up.
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n-> 0 = m
m^m -> 1
Again, an invalid value is no use. The math geeks are too strict.
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#Joe Griffin
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Who cares what you think, Azurepudding? It's been proven that 0^0 is indeterminate, your opinion doesn't matter.
There's nothing special about assuming something false and arriving at a contradiction. It's called the principle of explosion, look it up.
did you even read my post? lol
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HeyNK wrote:Who cares what you think, Azurepudding? It's been proven that 0^0 is indeterminate, your opinion doesn't matter.
There's nothing special about assuming something false and arriving at a contradiction. It's called the principle of explosion, look it up.
did you even read my post? lol
The answer is no.
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#Joe Griffin
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HeyNK wrote:Who cares what you think, Azurepudding? It's been proven that 0^0 is indeterminate, your opinion doesn't matter.
There's nothing special about assuming something false and arriving at a contradiction. It's called the principle of explosion, look it up.
did you even read my post? lol
Uh, am I obligated to read your posts or something now? What, are you telling me all these words are math? No, sweetie, math is done in EQUATIONS. Don't pretend to be such a mathamatician, next time you post on MY childrens smiley game forum.
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Mathmeticans say 0/0 is invalid only because they don't want to violate that /0 is invalid. Proof 0/0 = 0:
0^2/0^1 = 0^1 = 0.
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#Joe Griffin
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Agreed
F
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the "high school algebra" starter pack
https://www.math.toronto.edu/mathnet/fa … t1eq2.html
https://www.math.hmc.edu/funfacts/ffile … .1-8.shtml
this thread
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Mathmeticans say 0/0 is invalid only because they don't want to violate that /0 is invalid. Proof 0/0 = 0:
0^2/0^1 = 0^1 = 0.
They aren't just doing it for the sake of it, 0/0 physically has to be undefined or the whole of maths doesn't work
I'm not so sure about 0^0, I haven't been able to find any concrete evidence for why it can't be 1 and a lot of people do seem to say they think it should be, but 0/0 definitely has to be undefined
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azurepudding wrote:HeyNK wrote:Who cares what you think, Azurepudding? It's been proven that 0^0 is indeterminate, your opinion doesn't matter.
There's nothing special about assuming something false and arriving at a contradiction. It's called the principle of explosion, look it up.
did you even read my post? lol
Uh, am I obligated to read your posts or something now? What, are you telling me all these words are math? No, sweetie, math is done in EQUATIONS. Don't pretend to be such a mathamatician, next time you post on MY childrens smiley game forum.
to prove 0^0 != 1
3^0 = 3/3 = 1
2^0 = 2/2 = 1
1^0 = 1/1 = 1
0^0 = 0/0...
undefined
simple bruh
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Squaare root of -1 used to break math. ^
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#Joe Griffin
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