Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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Regarding Subarrachnoid Hemorrhages.
There is about a 7.5 out of 100000 prevalence of Subarachnoid Hemorrhage every year.
My question is: how do you stretch this out into 78 years (average age of life expectancy)? I thought you just took 7.5 divided by 100000, and then multiplied the result by 78, but that is NOT how it works. Does anyone know how to make this work? Thanks.
What are you trying to find out? The chance of a person having at least one in their lifetime?
If so, you were counting the number of hemorrhages in the average persons lifetime, but someone could get one twice, which you wouldnt want to treat this as two
For this sort of thing, its much easier to work out the probability of not getting one.
To do this, first get the chance of not getting one in a year (99992.5 in 100000), then to work out the chance of something happening (or not happening) multiple times, you multiply the chances together. You need to do this 78 times, so you can do ((99992.5 / 100000) ^ 78)
This leaves you with a chance of 0.99416685982, and all you need to do is subtract it from one, then you get the chance of having a hemorrage during your life, 0.00583314018 or roughly 0.583%
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Perfect! Thank you. I took statistics last year so I was getting really worked up haha. Forgot everything already
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