Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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So I have rolled 2 dices 1,000 times and recorded the total number. Here's what I came up with, just in-case you need it for Monopoly or what-not. I did it virtually of course
2=2%
3=6.1%
4=8.1%
5=11.9%
6=14%
7=16.2%
8=13%
9=10.1%
10=9.6%
11=6%
12=2.9%
I'm in love with a dragon <3
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That's great, but overall, no dice has two of the same number on two of its side. With that fact, I believe it just really depends on how you roll it. :3
Correct me if I'm wrong.
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You rolled dice 1000 TIMES!!!
And there are much, much more accurate ways to do this. You can just do a little algebra and then you would have it. For instance, a 2 and a 12 should be relatively close, but in your experiment they are almost a whole percentage off.
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Damn you.
Are the dice the same?
Is there an even chance to land on each number?
There is a .1666666667 chance to land on each number so it's a fair even chance and both of the dices are 6-sided dices, not paper made, because I can make paper dices. They're the ones you get from a board game.
I'm in love with a dragon <3
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Wow,That takes dedication! + Rep just for spending ur time on that
This is nice practical approval, however in theory it was already done.
*PREPARE FOR A HIGHLY MATHEMATICAL POST*
Dice 1 Dice 2
1 1
2 2
3 3
4 4
5 5
6 6
Those are simply all the numbers you can get on both dice. If you add up the possibilities:
1+1=2 2+1=3 3+1=4 4+1=5 5+1=6 6+1=7
1+2=3 2+2=4 3+2=5 4+2=6 5+2=7 6+2=8
1+3=4 2+3=5 3+3=6 4+3=7 5+3=8 6+3=9
1+4=5 2+4=6 3+4=7 4+4=8 5+4=9 6+4=10
1+5=6 2+5=7 3+5=8 4+5=9 5+5=10 6+5=11
1+6=7 2+6=8 3+6=9 4+6=10 5+6=11 6+6=12
Here's a small frequency table to list all the numbers above:
ROLLED NUMBER | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12
FREQUENCY | 1 | 2 | 3 | 4 | 5 | 6 | 5 | 4 | 03 | 02 | 01
As you can see, in all throwing possibilities the 7 got thrown with 6 different possibilities.
36 total throws.
ROLLED NUMBER PERCENTAGE
02 | 2.778%
03 | 5.556%
04 | 8.333%
05 | 11.111%
06 | 13.889%
07 | 16.667%
08 | 13.889%
09 | 11.111%
10 | 8.333%
11 | 5.556%
12 | 2.778%
Basically, if the dice are not rigged or out of balance, and all sides have equal chances of being thrown, the closer the rolled number is to 7, the more often it is thrown.
If you were to put it in a graph, it would look like a mountain.
There is a .1666666667 chance to land on each number so it's a fair even chance and both of the dices are 6-sided dices, not paper made, because I can make paper dices. They're the ones you get from a board game.
That's great, but overall, no dice has two of the same number on two of its side. With that fact, I believe it just really depends on how you roll it. :3
Correct me if I'm wrong.
That chance is for 1 dice at a time. with multiple dice, it's alot different, as shown in my above graphs.
As you can see, the difference between 1 and 2 dice is huge!
Last edited by BorkD (Dec 8 2011 8:48:11 am)
2=2%
3=6.1%
4=8.1%
5=11.9%
6=14%
7=16.2%
8=13%
9=10.1%
10=9.6%
11=6%
12=2.9%
ROLLED NUMBER PERCENTAGE
02 | 2.778%
03 | 5.556%
04 | 8.333%
05 | 11.111%
06 | 13.889%
07 | 16.667%
08 | 13.889%
09 | 11.111%
10 | 8.333%
11 | 5.556%
12 | 2.778%
That seems legit, same pattern as my results except your results was came up mathematically.
I'm in love with a dragon <3
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Wow,That takes dedication! + Rep just for spending ur time on that
Lol, read the black text. He just clicked a little button and it did it for him.
Pawlowic wrote:Wow,That takes dedication! + Rep just for spending ur time on that
Lol, read the black text. He just clicked a little button and it did it for him.
I Phailed. Im a blind man :I
No, you are a man who cannot read black. Even worse!!!!one!!!
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For monopoly, it wouldn't matter, you roll whatever you roll, and have to go with it. However, it backgammon, one of the most awesome games ever, it matters a lot.
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