Do you think I could just leave this part blank and it'd be okay? We're just going to replace the whole thing with a header image anyway, right?
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If you can find the missing terms in this 15th term sequence then I will give you a virtual cookie:
Term number: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Value: ?, 9, 18, 31, ?, ?, ?, 114, ?, 174, 209, ?, ?, ?, 380,
As you can see the terms 1, 5, 6, 7, 9, 12, 13, and 14 are missing but the 2nd, 3rd, 4th, 8th, 10th, 11th and 15th terms are given.
I'd appreciate it if anyone would like to waste their time and find the missing terms just to satisfy my curiosity that I am too lazy to satisfy myself. It might not even be possible but idk.
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idk is it 3 or something
lunchbox
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I found a parabola with the first values as X and second values as y using the points (2,9), (8,114), and (15,380) and got y = (41/26)x^2+(45/26)x-(10/13). The rest of the points to seem to be the floors of the y value (always round down like (3,18.6153846154) becomes (3,18)). So the complete table would be: (1,2) (2,9) (3,18) (4,31) (5,47) (6,66)o: (7,88) (8,114) (9,142) (10,174) (11,209) (12,247) (13,288) (14,332) (15,380)
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I found a parabola with the first values as X and second values as y using the points (2,9), (8,114), and (15,380) and got y = (41/26)x^2+(45/26)x-(10/13). The rest of the points to seem to be the floors of the y value (always round down like (3,18.6153846154) becomes (3,18)). So the complete table would be: (1,2) (2,9) (3,18) (4,31) (5,47) (6,66)o: (7,88) (8,114) (9,142) (10,174) (11,209) (12,247) (13,288) (14,332) (15,380)
Oh wow thanks. You have earned your virtual cookie . You have satisfied my curiosity for how many KB the code I am writing would have been if I saved at different points and for that I am grateful.
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Om nom nom, any time c: thanks for the cookie
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